x^2+60x-875=0

Solution for x^2+60x-875=0 equation:

x^2+60x-875=0

a = 1; b = 60; c = -875;
Δ = b2-4ac
Δ = 602-4·1·(-875)
Δ = 7100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7100}=\sqrt{100*71}=\sqrt{100}*\sqrt{71}=10\sqrt{71}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10\sqrt{71}}{2*1}=\frac{-60-10\sqrt{71}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10\sqrt{71}}{2*1}=\frac{-60+10\sqrt{71}}{2}
$